How You Can Own Floor Tiles For The Bathroom


To do this, you would like to understand the entire quadrature of the space , which is calculated consistent with standard geometric formulas in this case for the square: 1.73 × 1.73 = 3.46 m2, the number is rounded and gets an area of   3.5 m2. Then you need to find out the area of   one floor tile: 0.335 × 0.335 = 0.112 m2.

Now they determine how many whole tiles are needed to tile the whole area: 3.5 / 0.112 = 31.2 pieces. The amount is rounded to 32 and adds 10% for the wedding and pruning, in the case of a diagonal layout – 15%. The total is 35 or 37 tiles respectively.

The second method is considered more accurate, the tiles are calculated separately. Calculate how many tiles fit along one of the sides of the floor (width): 1.73 / 0.335 = 5.2 rounded to 6. Now calculate the number of tiles that fit along the adjacent wall (floor length): 1.73 / 0.335 = 5, 2, also rounded to 6, in this case the result is similar. The calculations show that 5 whole tiles and trim are laid along each wall.

Now they will discover how much material is needed: 6 × 6 = 36 pieces. Given that the number has increased by almost one when rounding off, the correction for battle and marriage is introduced only in the case of a diagonal layout – 5%.

Wall Tile

To calculate the specified number of wall tiles, you would like to seek out the perimeter of the bathroom: (1.73 + 1.73) 2 = 6.92 m, rounded to 7 m. Now calculate the length of one tile, how many pieces there are stacked in a row around the perimeter of the room 7 / 0.2 = 35 pcs.

The layout of the tiles in this case implies a dark bottom, it is usually raised to a height of about 1 m. But since no cropping is required, the height may vary depending on the dimensions of the selected tile: 1 / 0.3 = 33, three rows are the best option.

The total number of dark tiles in three rows is determined: 35 × 3 = 105, add 3 pieces to the battle, total – 108 dark tiles.

  Dark and light tiles are usually separated by a border. The length of the frieze in this case is similar to the length of the tile – 0.2 m, but it fits only in one row, that is, to lay the curb along the perimeter, 35 elements are required.

Now you need to calculate the number of rows of light tiles and the total number. It is known that the height of the room is 2.6 m, the height of the dark layer is 0.9 m and the edge is 00.8 m. It turns out 2.6 – 0.9 – 00.8 = 1 , 62 m – the height of the light layer. Divide the resulting number by the height of the tile and get the number of rows 1.62 / 0.3 = 5.4, i.e. 5 rows of the whole tile and trim below the ceiling.

Recognize the total number of light tiles 35 × 5.4 = 189. In this case, the number cannot be rounded to 6 because less than half of a tile is trimmed in the last row. 4 additional tiles have also been added to the total.

  The layout of the tile suggests the presence of decors in a bright area, only 3 pieces on three walls and 2 elements on the wall with a doorway. Total: (3 × 3) + 2 = 11 elements. This number must be subtracted from the total number of light tiles 193-11 = 182.

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Dark Bottom, Light Top – Classic

When calculating wall tiles, don’t ditch the presence of a doorway, the height is 2 m, the width is 0.7 m. A certain number of tiles can be safely deducted from the total number and saved a little.

  First, they figure out how many whole tiles fit in one row at the height of the opening: 2 / 0.3 = 6.6, here they are rounded to a smaller one – 6 pieces. Now count the number of tiles per door width: 0.7 / 0.2 = 3.5, also rounded to a smaller – 3 tiles.

The height of the dark layer is known to be 3 rows, 3 × 3 = 9 tiles of dark color. The frieze has the same length as the tile, respectively 3 elements fit the width of the doorway.

  Now calculate the number of rows of solid light tile (2-0.9-0.08) /0.3 = 3.4, ie 3 rows of light tile. The amount of light tiles that can be subtracted is determined: 3 × 3 = 9 pcs.

 In the same way, determine the amount of excess tiles for window openings, as well as for areas that are not tiled, for example, behind the bathroom.

End Result

Floor tiles required – 36 pcs.;

Dark tiles – 94 pieces + 3 spare parts;

Light tiles – 169 pieces + 4 pieces. spare parts;

Strips – 32 pcs. + 1 pc. in reserve;

Decors – 11 pieces + 1 spare.

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